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Mnenie [13.5K]
3 years ago
9

James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air conditione

d rooms. He then measured the growth of the pea plants after a week. In this experiment sunlight is a(n) ____.
A. independent variable

B. Constant

C. Dependent variable

D. Control
Chemistry
2 answers:
MariettaO [177]3 years ago
4 0
<span>C. Dependent variable  without the sunlight he could not preform his experiment because if he where to put both in the sunlight the sunlight would then become control but it could never become independent </span>
Umnica [9.8K]3 years ago
3 0

Answer:

independent variable

Explanation:

this is the correct answer

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2-butanone is converted into 3-methyl-3-hexanol using a grignard reagent prepared from 1-bromopropane and magnesium metal in thf
Andre45 [30]

Answer:

Here's what I get.

Explanation:

At the end of the reaction you will have a solution of the alcohol in THF.

The microdistillation procedure will vary, depending on the specific apparatus you are using, but here is a typical procedure.

  • Transfer the solution to a conical vial.
  • Add a boiling stone.
  • Attach a Hickman head (shown below) and condenser.
  • Place the assembly in in the appropriate hole of an aluminium block on top of a hotplate stirrer.
  • Begin stirring and heating at a low level so the THF (bp 63 °C) can distill slowly.
  • Use a Pasteur pipet to withdraw the THF as needed.
  • When all the THF has been removed, raise the temperature of the Al block and distill the alcohol (bp 143 °C).

7 0
4 years ago
Surface tension explains which of the following
dexar [7]
I'm pretty sure the answer is 1. I and III
3 0
3 years ago
Read 2 more answers
Explain the importance of replication in scientific research
SVEN [57.7K]

Answer:

Explanation:

Replication is crucial to science. Every time researcher find something surprising that has to do with science they replicate it.

8 0
3 years ago
Read 2 more answers
What is the ph of a 0.006 m koh solution? 1. 11.78 2. 7.00 3. 2.22 4. 8.88 5. 5.12?
Stels [109]
The concentration of OH⁻ is first converted to pOH bu using followinf formula,

                                           pOH  =  -log [OH⁻]
Putting value,
                                           pOH  =  -log (0.006)

                                           pOH  =  2.221
As we know,
                                   pH + pOH  =  14
Solving for pH,
                                   pH  =  14 - pOH
Putting value of pOH,
                                   pH  =  14 - 2.221

                                   pH  =  11.779
Result:
           Option-1
is the correct answer.
4 0
3 years ago
A mixture of XO2 (P = 3.00 atm) and O2 (P = 1.00 atm) is placed in a container. This elementary reaction takes place at 27 °C: 2
sukhopar [10]

Answer:

a) \triangle G^{0} = 7.31 kJ/mol

b) K_{-1} = 0.0594 m^{-1} s^{-1}

Explanation:

Equation of reaction:

                                     2 XO_{2} (g) + O_{2} (g) \rightleftharpoons 2XO_{3} (g)

Initial pressure                  3              1              0

Pressure change             2P           1P             2P

Total pressure = (3-2P) + (1-P) + (2P)

Total Pressure = 3.75 atm

(3-2P) + (1-P) + (2P) = 3.75

4 - P = 3.75

P = 4 - 3.75

P = 0.25 atm

Let us calculate the pressure of each of the components of the reaction:

Pressure of XO2 = 3 - 2P = 3 - 2(0.25)

Pressure of XO2 =2.5 atm

Pressure of O2 = 1 - P = 1 -0.25

Pressure of O2 = 0.75 atm

Pressure of XO3 = 2P = 2 * 0.25

Pressure of XO3 = 0.5 atm

From the reaction, equilibrium constant can be calculated using the formula:

K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }

K_{p} = \frac{0.5^2}{2.5^2 *0.75} \\K_{p} = 0.0533 = K_{eq}

Standard free energy:

\triangle G^{0} = - RT ln k_{eq} \\\triangle G^{0} = -(0.008314*300* ln0.0533)\\\triangle G^{0} = 7.31 kJ/mol

b) value of k−1 at 27 °C, i.e. 300K

K_{1} = 7.8 * 10^{-2} m^{-2} s^{-1}

K_{c} = K_{p}RT\\K_{c} = 0.0533* 0.0821 * 300\\K_{c} = 1.313 m^{-1}

K_{-1} = \frac{K_{1} }{K_{c} } \\K_{-1} = \frac{7.8 * 10^{-2}  }{1.313 }\\K_{-1} = 0.0594 m^{-1} s^{-1}

6 0
3 years ago
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