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german
2 years ago
11

I will mark the best answer as brainliest.

Mathematics
2 answers:
dimulka [17.4K]2 years ago
6 0

Answer: They didn't solve the problem all the way, you need to find the square root of 674. The final answer is 25.96

Step-by-step explanation:

a^{2} + b^{2}= c^{2}

7^{2} + 25^{2} = 674

\sqrt{674} = 25.96

Arte-miy333 [17]2 years ago
5 0

Answer:

= sq rt 576

25^2 - 7^2 = c^2

25^2 - 7^2 =c^2

sq rt 576  = c^2    

Answer is sq rt 576  it is not sq rt 674 = c^2 as we are given the hypotenuse to square and so we subtract b^2 from it to give a^2

we can use hypotenuse and any right angle side b^2 to find a^2

c^2 - b^2 = a^2 is formula

25^2 - 7^2 = a^2

25^2 - 7^2 =a^2

sq rt 576  = a^2  

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Mia wants to buy 3 notebooks for $1.29 each. What is the expression for the total cost?
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Mia want to buy 3 notebook for $1.29 each ,

then total cost =3×1.29

hence, 3×29

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Cassie received a 20%-off coupon and a $10-off coupon from a department store. She visits the department store during a tax-free
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  B.  The original purchase total must be at most to $44 before the discounts are applied.

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4 0
3 years ago
Free brainliest if you can convert this fraction into a decimal: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%CF%80%7D%7Be%7D" i
ioda

Answer:

We all know that 22/7 is a very good approximation to pi. But this well-known fraction is is actually 1/791 larger than a slightly less-well-known but much more mysterious rational approximation for pi: . The fraction 355/113 is incredibly close to pi, within a third of a millionth of the exact value.

Step-by-step explanation:

6 0
3 years ago
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5k^3-8-4k^2+5k^2-2+3k^3
lara31 [8.8K]
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>

-----------------------------------------------------------------------

5k^3-8-4k^2+5k^2-2+3k^3

Group like terms:

5k^3+3k^3-4k^2+5k^2-8-2

Add similar elements:

5k^3+3k^3+k^2-8-2

Add similar elements:

8k^3+k^2-8-2

Subtract the numbers:

8k^3+k^2-10

Your Answer Is 8k^3+k^2-10

Plz mark me as brainliest :)

7 0
3 years ago
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