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zhannawk [14.2K]
2 years ago
8

A man borrowed $8000. He paid $10100 after 9 months for the debt. What was the interest rate per annum?

Mathematics
1 answer:
Anastaziya [24]2 years ago
4 0

Answer:

3.5%

Step-by-step explanation:

Interest = 10100 - 8000 or 2100

I = Prt

2100 = 8000(9/12)r

2100 = 600r

2100/600 = r

3.5 = r

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What is 2/7 divided by 7/8<br><br> please help me fine the answer to the question
dmitriy555 [2]

Answer:

16/49

i dont have an explaination i just used somthing but it wont let me say it  uh yea

4 0
3 years ago
Runners race around a rectangular park during the city marathon. The length of the park is 6 miles. The width of the park is 7 m
Otrada [13]
Hi there! The answer is A. miles

We can find the miles someone would run during the marathon, by using the formula for the perimeter. This is:
2 × width + 2 x length.

Filling in this formula learns us that the distance that is run is measured in miles. The answer is A.
8 0
3 years ago
) The National Highway Traffic Safety Administration collects data on seat-belt use and publishes results in the document Occupa
asambeis [7]

Answer:

We conclude that there is a difference in seat belt use.

Step-by-step explanation:

We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.

<u><em>Let </em></u>p_1<u><em> = population proportion of drivers 16-24 years old who buckle up .</em></u>

<u><em /></u>p_2<u><em> = population proportion of drivers 25-69 years old who buckle up .</em></u>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no significant difference in seat belt use}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a difference in seat belt use}

The test statistics that would be used here <u>Two-sample z proportion statistics;</u>

                     T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers 16-24 years old who buckle up = 79%

\hat p_2 = sample proportion of drivers 25-69 years old who buckle up = \frac{924}{1100} = 84%

n_1 = sample of 16-24 years old drivers = 1000

n_2 = sample of 25-69 years old drivers = 1100

So, <u><em>test statistics</em></u>  =  \frac{(0.79-0.84)-(0)}{\sqrt{\frac{0.79(1-0.79)}{1000}+\frac{0.84(1-0.84)}{1100} } }  

                              =  -2.946

The value of z test statistics is -2.946.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u><em>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that there is a difference in seat belt use.

4 0
3 years ago
The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with
pochemuha

Answer:

a)17.92

b) 16.83 .... 21.17

Step-by-step explanation:

ρ→   z

0.14 = -1.080319341

-1.080 = (x - 19)/1 = 17.92

~~~~~~~~~~~~~~~~~~

3% / 2 = 1.5%

1.5% - 98.5%

ρ→   z

0.015 = -2.170090378 ....  -2.17 = (x-19) =16.83

0.985 = 2.170090378  ....   2.17 = (x-19) =21.17

8 0
3 years ago
What is 20/10 as a mixed number?
nadya68 [22]
Hello there!
the answer is 2

Hope this helps! :)
~zain
8 0
3 years ago
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