$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$600\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\to &1\\ t=years\to &8 \end{cases} \\\\\\ A=600\left(1+\frac{0.08}{1}\right)^{1\cdot 8}\implies A=600(1.08)^8\implies A\approx 1110.558126$

8 0

3 years ago

The population of a city has increased by 33% since it was last measured. If the current population is 39,900, what was the prev

Ksju [112]

Answer:

26,733

Step-by-step explanation:

39,900 - Percentage decrease =

39,900 - (33% × 39,900) =

39,900 - 33% × 39,900 =

(1 - 33%) × 39,900 =

(100% - 33%) × 39,900 =

67% × 39,900 =

67 ÷ 100 × 39,900 =

67 × 39,900 ÷ 100 =

2,673,300 ÷ 100 =

26,733

Hope this helps :)

5 0

4 years ago

PLEASE HELP ASAP! WILL GIVE BRAINLIEST

goldenfox [79]

This should be right.

Part A:

-mk - 110 > 75

-mk > 185

m < 185/-k (Fraction)

m < - 185/k (Fraction)

Part B:

2c - 8f + 24

-8f = 24 - 2c

f = 24/-8 -2c/-8

f = 3 + 1/4 c

3 0

3 years ago