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mafiozo [28]
3 years ago
14

If the airplane had to return to the airport, how far would it have to travel?

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Step-by-step explanation:

Draw a line connecting the plane to the airport

then using Pythagoras theorem u can get d distance from the plane to d airport

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Given only the information in the diagram, determine if m is parallel to n. If so, name the postulate or theorem used to support
Advocard [28]

Answer:

<em><u>From my research on the internet, the image attached supports this problem. The two lines are parallel, as supported by the converse of corresponding angles postulate. It states that: If a transversal intersects two lines and the corresponding angles are congruent, then the lines are parallel.</u></em>





8 0
3 years ago
A) The coefficient in the expression -3x + 1 is
mihalych1998 [28]

Step-by-step explanation:

A coefficent is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. Or in other words, the number being multiplied with the variable. For example, the 4 in 4x.

The expression is -3x + 1. If we go back to the definition, the coefficient is the number combined with the variable.

So the answer is -3.

Hope it helps!

3 0
4 years ago
Can I get some help I’ll mark brainliest
iren2701 [21]
Itzzzzz 13/15 in simplest form
4 0
3 years ago
PLEASE HELP!!! 15 POINTS!!
tankabanditka [31]

Answer:

23.4 cm

Step-by-step explanation:

If the base of the triangle is half of that of a given side, then we need to divide the given side by 2 to get the base.

46.8

---------2

23.4

There is your answer

Hope it helped

Bye

7 0
3 years ago
Read 2 more answers
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
zhenek [66]

ANSWER

The vertical asymptotes are


\Rightarrow x=2\:or\:x=-1

<u>EXPLANATION</u>

We have

f(x)=\frac{x^2+4}{4x^2-4x-8}


For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

4x^2-4x-8=0


\Rightarrow x^2-x-2=0

We split the middle term to obtain,

x^2+x-2x-2=0

\Rightarrow x(x+1)-2(x+1)=0


\Rightarrow (x-2)(x+1)=0


\Rightarrow x=2\:or\:x=-1


Therefore the vertical asymptotes are


x=2\:or\:x=-1





3 0
4 years ago
Read 2 more answers
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