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AveGali [126]
3 years ago
10

Can you help me please ​

Mathematics
1 answer:
Volgvan3 years ago
8 0
$5000 I think should be right
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Question 17 please help
kramer
\sqrt{9x^2} / \sqrt{18y^2}
after taking sqrt both side

3x/\sqrt{9*2y^2}

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y

Answer is A

8 0
3 years ago
4x−4y=-2 and −9x−4y ​ =-3 solve by adding please !!!
jeyben [28]
1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️
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Naddika [18.5K]

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Step-by-step explanation:

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10 POINTS HELP PLEASE HURRY !!!
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b

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