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2 years ago

7

En una prensa hidráulica, el pistón pequeño tiene un diámetro de 12 cm y el pistón grande tiene un diámetro de 3 m ¿Qué fuerza s

e requiere aplicar en el pistón pequeño para levantar un peso de 7848 N con el pistón grande?

1 answer:

Licemer1 [7]2 years ago

3 0

Answer:

i dont know what is that language

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The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?

Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole = $\frac{1}{3} \pi r^2 h$

So, Volume of conical hole = $\frac{1}{3} \pi \times r^2 \times 9$

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So, $\frac{1}{3} \pi \times r^2 \times 9=75 \pi$

$\frac{1}{3} \times r^2 \times 9=75$

$r^2=\frac{75 \times 3}{9}$

$r=\sqrt{\frac{75 \times 3}{9}}$

r=5

Hence The radius of hole is 5 feet

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3 years ago

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wolverine [178]

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Step-by-step explanation:

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