3 years ago

Find the radius of a circle in which an inscribed square has a side of 8 inches.

2 answers:

4 0

If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.

d^2=x^2+x^2

d^2=2x^2

d=√(2x^2)

Since d=2r, r=d/2 so

r=(1/2)√(2x^2)

r=√((2x^2)/4)

r=√(x^2/2), since x=8

r=√(64/2)

r=√32

r=√(16*2)

r=4√2 in (exact)

r≈5.66 in (to nearest hundredth of an inch)

Vladimir79 [104]3 years ago

4 0

Answer: 4^2

Step-by-step explanation:

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Natali5045456 [20]

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6 0

3 years ago

Can someone please help me with this!!

Aloiza [94]

Answer:

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