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poizon [28]
3 years ago
15

Find the radius of a circle in which an inscribed square has a side of 8 inches.

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.

d^2=x^2+x^2

d^2=2x^2

d=√(2x^2)

Since d=2r, r=d/2 so

r=(1/2)√(2x^2)

r=√((2x^2)/4)

r=√(x^2/2), since x=8

r=√(64/2)

r=√32  

r=√(16*2)

r=4√2 in (exact)

r≈5.66 in (to nearest hundredth of an inch)
Vladimir79 [104]3 years ago
4 0

Answer: 4^2

Step-by-step explanation:

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Question
Mashutka [201]

The equivalent value of given the expression is -17.25. Therefore, option C is the correct answer.

<h3>What is an equivalent expression?</h3>

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

The given expression is -14-8×0.5+0.75.

Now, -14-8×0.5+0.75

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The equivalent value of given the expression is -17.25. Therefore, option C is the correct answer.

To learn more about an equivalent expression visit:

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Two integers, a and b have a product of 15. what is the least possible sum of a and b?
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