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4 years ago

Find the radius of a circle in which an inscribed square has a side of 8 inches.

2 answers:

4 0

If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.

d^2=x^2+x^2

d^2=2x^2

d=√(2x^2)

Since d=2r, r=d/2 so

r=(1/2)√(2x^2)

r=√((2x^2)/4)

r=√(x^2/2), since x=8

r=√(64/2)

r=√32

r=√(16*2)

r=4√2 in (exact)

r≈5.66 in (to nearest hundredth of an inch)

Vladimir79 [104]4 years ago

4 0

Answer: 4^2

Step-by-step explanation:

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wariber [46]

Answer:

the other sides are 9 and 12

Step-by-step explanation:

use the Pythagorean theorem.

a^{2} +b^{2} =c^{2}

you know that c^2 is 225 because 15*15=225

a^{2} +b^{2} =225

(from here on I just plugged numbers in)

3:4=9:12

9^{2} +12^{2} =225

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225=225

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3 years ago

Inqualities question pls help!

Margaret [11]

Answer:

Step-by-step explanation:

The closed circle at - $\frac{3}{2}$ indicates that x can equal this value

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Answer:

3. 26 problems left

4. $69.20

Step-by-step explanation:

1. First I divided 5 into 2 to get a decimal, 0.4, and then I multiplied 0.4 to 65.

0.4 x 65 = 26

2. It said that Luke paid 2.75 for himself and 6 other friends, which is 7 people. I then multiplied 2.75 x 7 and got 19.25. I then added 19.25 to the other amount of money, and got 69.20.

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2 years ago