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poizon [28]
3 years ago
15

Find the radius of a circle in which an inscribed square has a side of 8 inches.

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.

d^2=x^2+x^2

d^2=2x^2

d=√(2x^2)

Since d=2r, r=d/2 so

r=(1/2)√(2x^2)

r=√((2x^2)/4)

r=√(x^2/2), since x=8

r=√(64/2)

r=√32  

r=√(16*2)

r=4√2 in (exact)

r≈5.66 in (to nearest hundredth of an inch)
Vladimir79 [104]3 years ago
4 0

Answer: 4^2

Step-by-step explanation:

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7 0
2 years ago
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LMNO is a parallelogram. If NM = x + 15 and OL = 3x + 5, find the value of x
Sidana [21]
<span>LMNO is a parallelogram
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Answer
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