(3x - 1)(3 -x)+x^2 + 19
a)
(3x - 1)(3 -x)+x^2 + 19
=9x - 3x^2 - 3 + x + x^2 + 19
= -2x^2 + 10x + 16
b) evaluate at x = 2
-2x^2 + 10x + 16
= -2 (2^2) + 10(2) + 16
= -8 + 20 + 16
= 28
c)
from part (a)
-2x^2 + 10x + 16
= -2 (x^2 - 5x - 8) (complete factor)
Answer:
One answer exists for this equation.
One number<span> is eight </span>less than<span> five </span>times<span> another. </span>If the sum<span> of the </span>two numbers<span> is 28, find the </span><span>numbers . Please levae this i need points i have 0000
</span>
Answer: In the last steps, instead of multiply each side by 3, he has to divide each side by 3.
Step-by-step explanation:
Hi, Tobin makes the mistake in the last steps.
3(x-1.25) = 11.25
3x-3.75= 11.25
3x-3.75+3.75= 11.25+3.75
3x = 15
Until this step is the work ok.
Now, instead of multiply each side by 3, he has to divide each side by 3:
So:
3x /3 = 15/3
x = 5
Feel free to ask for more if needed or if you did not understand something.
Answer:
.6
Step-by-step explanation:
