Hello :
<span>2(4w + 8) – 2w + 42 > 78
8w+16-2w+42 </span>> 78......(<span>distributivity × for + )
6w </span>> 20
w > 20/6
Answer: yes
Step-by-step explanation:
Ok!
(f^-1)'(a)=1/f'(f^-1)'(a)
f(a) =3 = 3+x^2+tan(pi(x)/2),
0= 3+x^2+tan(pi(x)/2)
<span>(f^-1)'(a)
= 1/[f ' ( f^-1(a) )]
(f^-1)'(3)
= 1/[f ' ( f^-1(3) )]
(f^-1)'(3)
= 1/[f ' ( 0 )]
(f^-1)'(3)
</span>=0+1/2pie(1)
=pi/2
hope it helps
Answer:
s(t)=8t
Step-by-step explanation:
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second.
Let the length of the Square = s
We solve the differential equation above subject to the given initial condition.
The formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing is:
s(t)=8t (in cm)
Answer:
The answer is A.
Step-by-step explanation: