Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
Answer:
∠1 = 148°
Step-by-step explanation:
the triangle interior angles = 180°
the unknown interior angle = 180° - 82° - 66° = 32°
∠1 = 180° - 32° = 148° because it is supplementary to 32° (adds together to total 180°)
Line 1 as filled in curcle means smaller/bigger or equal to
Answer:
Youu can call the breadth x and then, as the length is two times the breadth, it would be 2x.
So now when we call x to the breadth and 2x to the length we can do an equation, as we know the sum of the four sides is 300 meters, so
2x + 2x + x + x = 300
6x = 300
x = 300/6 = 50
We know that the breadth is 50m, and, the length, which is twice the breadth, would be 100m in this exercise.
SO in this case, the breadth is 50 meters and the length is 100 meters..
