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denis-greek [22]
3 years ago
15

(3x2 – 5x + 6) + (2x2 + 7x - 9)

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

3x^2 + 2x^2 - 5x + 7x + 6 - 9

5x^2 + 2x - 3

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Mekhanik [1.2K]

Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>C</em><em> </em><em>1</em><em>/</em><em>3</em><em>2</em><em> </em><em>I</em><em>b</em>

Step-by-step explanation:

hope it helps

3 0
3 years ago
Which number is a counting number? Can you do both of them plz
DochEvi [55]
Question 3 is: D. All integers are rational numbers.
Question 4 is: C. the counting number is 4. Hope this helped :)
4 0
2 years ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
Ms. Ramos has
oksian1 [2.3K]

Answer:

63

Step-by-step explanation:

4 0
3 years ago
Plz some one look at this
aleksklad [387]
5 : - 1/6 = 0.167     out of 10 = 1.67  out of 100 = 16.7

even number  0.33 out of 10:-  3.3 out of 100:-  33

a prime number  0.5 out of 10: 5 and out of 100:- 50

multipl of 3:- 0/33  out of 10:- 3.3 and out of 100: 33
4 0
3 years ago
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