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ivanzaharov [21]
3 years ago
12

Bro please help I will Mark you as brainlist

Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

the first one is, yes by AA

the second is no you cannot

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What is the slope and y-intercept for 7x+2y-15=13
Orlov [11]

Answer:

-3.5 14

Step-by-step explanation:

2y=-7x+28

y=-3.5x+14

5 0
2 years ago
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Someone help me on this please!
swat32

Answer:

x = 15 cm


Step-by-step explanation:


All the ratio of corresponding sides should be equal


10 corresponds to x

16 corresponds to 24

12 corresponds to 18


<em>Finding the ratio of the known pairs:</em>

  • \frac{16}{24}=\frac{2}{3}
  • \frac{12}{18}=\frac{2}{3}

<em>Similarly 10 is to x should be 2 is to 3. Finding x:</em>

\frac{10}{x}=\frac{2}{3}\\10*3=2x\\30=2x\\x=\frac{30}{2}\\x=15


So x = 15.

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3 years ago
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Write the quadratic equation in general form.
MrRa [10]

Answer: C

<u>Step-by-step explanation:</u>

(x - 3)² = 0

(x - 3)(x - 3) = 0

x(x - 3)  -3(x - 3) = 0

x² - 3x  -3x + 9  = 0

x² - 6x + 9  = 0

4 0
3 years ago
I'm so stuck, I would really appreciate help !
viktelen [127]
17 feet...use Pythagorean theorem to solve the length of the four hypotenuse of the four triangles you can produce from that shape.
4 0
4 years ago
A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = \frac{1}{60} degree

so angle of elevation at point C = 14 + \frac{52}{60}

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + \frac{10}{60} = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = \frac{200}{BC}

0.2655 =  \frac{200}{BC}

BC = \frac{200}{0.26552}

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = \frac{200}{BD}

1 = \frac{200}{BD}

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

     = 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0
3 years ago
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