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o-na [289]
2 years ago
7

Find a8 when a1= 9, d = 4 of the arithmetic sequence whose first term is a1 and common difference is d.

Mathematics
1 answer:
Gelneren [198K]2 years ago
5 0

<u>G</u><u>e</u><u>n</u><u>e</u><u>r</u><u>a</u><u>l</u><u> </u><u>A</u><u>r</u><u>i</u><u>t</u><u>h</u><u>m</u><u>e</u><u>t</u><u>i</u><u>c</u><u> </u><u>T</u><u>e</u><u>r</u><u>m</u><u>s</u>

\displaystyle \large{a_n = a_1 + (n - 1)d}

We want to find a8; we know:

  • a1 = 9
  • d = 4

Substitute in the formula.

\displaystyle \large{a_n = 9 + (n - 1)4} \\   \displaystyle \large{a_n = 9 + 4n - 4} \\   \displaystyle \large{a_n = 4n + 5}

To find a8, substitute n = 8

\displaystyle \large{a_8= 4(8) + 5} \\   \displaystyle \large{a_8= 32 + 5} \\   \displaystyle \large{a_8= 37}

Hence, the 8th term of sequence is 37

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