Question

Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. You must show all of your work to receive credit.
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Answer 1

Answer:

Step-by-step explanation:

$\frac{20x+108}{20x+381}$ = $\frac{372}{589}$

589( 20x + 108 ) = 372( 20x + 381 )

11780x + 63612 = 7440x + 141732

4340x = 78120

x = 18

Answer 2

Answer:

x = 18

Step-by-step explanation:

First, let's find the ratios between the two triangles

We'll use AV and AC

372 ÷ 589 = 12/19

All of the sides of the smaller triangle are 12/19 of the bigger triangle

Now let's find x

We know that AU + UB = AB

So it's 20x + 108 + 273 = AB

12/19 of a bigger triangle side equals a small triangle side

(12/19)AB = AU

For this equation multiply both sides by 19/12 to isolate AB

(12/19)AB x 19/12 = AU x 19/12

AB = (19/12)AU

Now we have this

20x + 108 + 273 = (19/12)(20x + 108)

20x + 381 = (19/12)(20x + 108)

Distribute the 19/12

20x + 381 = 95/3x + 171

Move all like terms to one side

20x + 381 = 95/3x + 171

       - 171                 - 171

20x + 210 = 95/3x

- 20x           - 20x

Don't forget about common denominators

210 = 95/3x - 60/3x

210 = 35/3x

Multiply both sides by 3

210 x 3 = 35/3x x 3

630 = 35x

Divide both sides by 35

630/35 = 35x/35

x = 18