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2 years ago

Please give me a step by step explanation of how to solve this question WILL MARK AS BRAINLIEST!

Mathematics

1 answer:

vodomira [7]2 years ago

4 0

Answer:

2261

<h2>Step-by-step explanation:add them up $x_{123}$ </h2>

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Solve they system by addition 7x-2y=3 4x+5y=3.25

noname [10]

Answer: x = 2/7y + 3/7 and

x= -5/4y + 0.8125

Step-by-step explanation: Let's solve for x.

7x−2y=3

Step 1: Add 2y to both sides.

7x − 2y + 2y= 3 + 2y

7x = 2y + 3

Step 2: Divide both sides by 7.

7x/7 = 2y+3/7 this is for the second answer Step 1: Add -5y to both sides.

4x+5y+−5y=3.25+−5y

4x=−5y+3.25

Step 2: Divide both sides by

4/4 x 4 = −5y + 3.25/4

4 0

2 years ago

An elevator goes up 7 floors and then down 4 floors. What integer represents the change in the floor level?

Leokris [45]

+3

The elevator went up 7 floors, making the current integer +7. The elevator then went down 4 floors, so 7 - 4 is 3. The final answer representing the change in floor level is +3 (positive three.)

3 0

2 years ago

Read 2 more answers

Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely

Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

Two children, hence $n = 2$ .
Equally as likely to be a boy or a girl, hence $p = 0.5$ .

The probability of one of each is P(X = 1), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5$

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0

2 years ago

-0.5- 3.5<br> also please explain how to solve it !!!

Marrrta [24]

Answer:

-4

Explanation:

sorry its hard to explain

4 0

1 year ago

F(x, y, z) = yzexzi + exzj + xyexzk,c: r(t) = (t2 + 4)i + (t2 − 1)j + (t2 − 2t)k, 0 ≤ t ≤ 2(a) find a function f such that f = ∇

exis [7]

$\nabla f(x,y,z)=\mathbf f(x,y,z)=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f(x,y,z)}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\displaystyle\int yze^{xz}\,\mathrm dx=\dfrac{yz}ze^{xz}+g(y,z)$
$f(x,y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f(x,y,z)}{\partial y}=e^{xz}=e^{xz}\dfrac{\partial g(y,z)}{\partial y}$
$\implies\dfrac{\partial g(y,z)}{\partial y}=0\implies g(y,z)=h(z)$
$f(x,y,z)=ye^{xz}+h(z)$

$\dfrac{\partial f(x,y,z)}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\partial h(z)}{\partial z}$
$\implies\dfrac{\partial h(z)}{\partial z}=0\implies h(z)=C$
$f(x,y,z)=ye^{xz}+C$

8 0

2 years ago