I added all the numbers and I got 43,665
Answer: INDEiAaaaaaaaaaaaaaaa
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
The emf of a cell is mathematically given as
= 0.0532 v
<h3>What is the emf of a cell?</h3>
Generally, the equation for emf is mathematically given as
where,
Pb is lead
H is hydrogen
/ Pb has a standard reduction potential of -0.126 volts, while
/ has a standard reduction potential of 0.0 volts.
![[Pb^2^+] x [H^+]^2](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20x%20%5BH%5E%2B%5D%5E2)
= 0.126 - 0.059/2 log 1 / [0.57] x [0.09]^2
= 0.0532 v
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