Question

Find the z score that corresponds to P99, the 99th percentile of a standard normal distribution curve.

Answer 1

Answer:

D.  2.33

Step-by-step explanation:

Hint- We have to use Inverse Normal Probability Distribution function. This function returns the x-value given the probability region to the left of the x-value.

We have to calculate the z score of the 99th percentile of a standard normal distribution curve.

i.e the value of probability less than z is given as 99th percentile or 0.99

Using inverse normal probability distribution function, we get

$z=2.3263\approx 2.33$