Find the z score that corresponds to P99, the 99th percentile of a standard normal distribution curve.
1 answer:
Answer:
D. <em>2.33</em>
Step-by-step explanation:
Hint- We have to use Inverse Normal Probability Distribution function. This function returns the x-value given the probability region to the left of the x-value.
We have to calculate the z score of the 99th percentile of a standard normal distribution curve.
i.e the value of probability less than z is given as 99th percentile or 0.99
Using inverse normal probability distribution function, we get
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A would be your answer.
(I am going to assume that the set of numbers are multiplied by exponents.)
To solve you just need to calculate each one. Note that for positive exponents you move the decimal point to the right and negative exponents you move the decimal point to the left.
The first scientific notation would be equal to 2700 because you move the decimal point 3 places to the right, since the exponent is positive.
The second scientific notation would be equal to 0.00424 because you move the decimal point 3 places to the left, since the exponent is negative.
The third scientific notation would equal 470 because you move the decimal point 2 places to the right, since the exponent is positive.
The last scientific notation would equal 0.043 because you move the decimal point 2 places to the left, since the exponent is negative.
Answer:
29C3 = 3654
Step-by-step explanation:
What is applied here is combination that n - combination of r which is a subscript and the n - is a superscript.
- nCr = nPr/r!
- where nPr = n!/(n-r)!
- nCr = n!/(n-r)! r!
- And we are told to find 29C3, apply the formula and your results will be out.
Attached is the detailed explanation.
