13 < 2t + 3 < 27
13<2t+3 2t+3<27
13-3<2t 2t<27-3
10<2t 2t<24
10/2<t t<24/2
5<t t<12
5 < t < 12
Answer:
The parabola's axis of symmetry is x = -6
Step-by-step explanation:
Parabola general equation:
y = a*(x - r1)*(x - r2)
Equation given:
y = (-1/4)*(x + 2)*(x + 10)
a = -1/4
r1 = -2
r2 = -10
To check if the parabola passes through the point (2, 10) it is necessary to replace x = 2 and check the y-value, as follows:
y = (-1/4)*(2+ 2)*(2 + 10) = -12
Then, point (2, 10) is not included in the parabola.
If a > 0 then the parabola opens upward; if a < 0 then the parabola opens downward. Then, the parabola opens downward
Axis of symmetry:
h = (r1 + r2)/2
h = (-2 + -10)/2 = -6
Then, The parabola's axis of symmetry is x = -6
To find Parabola's vertex, replace with the axis of symmetry:
y = (-1/4)*(-6 + 2)*(-6 + 10) = 4
Therefore, the parabola has a vertex at (-6, 4)
Answer:
Step-by-step explanation:
let us assume
now
can be written as 
we know 
so 
now from above equation we can say that
The answer is B because it’s not a straight line and x can not have an exponent of 2 bc it will make it nonlinear
-2w)23x45(8w9x4) this might be right
