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liraira [26]
3 years ago
5

What is the range of the given function?

Mathematics
1 answer:
Fed [463]3 years ago
6 0

9514 1404 393

Answer:

  (b)  {yly = -9, -3, 0, 5, 7}

Step-by-step explanation:

The range is the set of y-values in the ordered pairs. It is usually convenient to list a set in alphanumeric order.

The second values of the ordered pairs are 0, -3, -9, 5, 7. So, the range is ...

  y ∈ {-9, -3, 0, 5, 7} . . . . . matches the second choice

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Which best decribes the meaning of the term theorem
STALIN [3.7K]

Answer:

A theorem is a general proposition not self-evident but proved by a chain of reasoning; a truth established by means of accepted truths.

Step-by-step explanation:

8 0
2 years ago
What fraction is equal to the decimal 0.32
dangina [55]
8/25 is the answer. Hope this helps.
6 0
3 years ago
Read 2 more answers
Lincoln went to the grocery store and purchased cans of soup and frozen dinners. Each can of soup has 250 mg of sodium and each
Ludmilka [50]
We can solve with a system of equations, and use c for the amount of cans of soup and f for the amount of frozen dinners.


The first equation will represent the amount of sodium. We know the (sodium in one can times the number of cans) plus (sodium in one frozen dinner times the number of dinners) is the expression for the total sodium. We also know the total sodium is 4450, so:


250c + 550f = 4450


The second equation is to find how many of each item are purchased:


c + f = 13


Solve for c in the second equation:


c = 13 - f


Plug this in for c in the first equation:


250(13-f) + 550f = 4450


3250 - 250f + 550f = 4450


300f = 1200


f = 4


Now plug the value for f into the second equation:


c + 4 = 13


c = 9


The answer is 9 cans of soups and 4 frozen dinners.


6 0
3 years ago
Read 2 more answers
Anyone know the answer to this algebra problem?
ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

<u>Step-by-step explanation:</u>

\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}

\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}

3 0
3 years ago
Please help me!! Lots of love!!
Marizza181 [45]

Answer:

D) 2

Step-by-step explanation:

write 8 in exponential form which is 2^3

now simplyfy the root which equals 2

2 is the answer.

4 0
2 years ago
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