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3 years ago

I need help ASAP!!Please help me

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

Below

Step-by-step explanation:

To find the volume of a rectangular prism find the area of a face and multiply it by the height

V = lwh

= (12)(5)(12)

= 720 km^3

Hope this helps!

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Find the greatest common factor of the terms in the following expression: 32rt – 12t.

velikii [3]

This is what I got use photo math

4 0

2 years ago

Help please!10 points

laila [671]

Answer:

The equation of the line is $y = 3x + 3$

Step-by-step explanation:

Looks like you've already found the y-intercept and slope of this graph. Great! That's all the info we need to create an equation.

The equation of a line is always in $y = kx+b$ form, where k is the constant of proportionality (aka the slope) and b is the constant added (aka the y-intercept).

We know the slope is 3 and the y-intercept is 3, so we can put these values into the equation.

$y = 3x+3$

Hope this helped!

3 0

3 years ago

Read 2 more answers

H(x) = -x - 1, find h(-2)

eduard

Answer:

I think the answer is 1

Step-by-step explanation:

-(-2)-1

6 0

3 years ago

Find the value of x.

Allisa [31]

A straight line is 180°, so you can do:

109 + ? = 180 (? is the top angle of the triangle)

? = 71°

Because the triangle is an isosceles triangle, the other angle is 71° too.

71 + 71 + ? = 180

? = 38

You subtract 38 with 90 to find the other angle.

90 - 38 = 52°

To find ∠2 you subtract 52 with 180.

180 - 52 = 128

∠2 = 128

128 = 11x + 18

110 = 11x

10 = x

5 0

3 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$

We have two roots:

$x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}$

ANswer:

$x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}$

6 0

3 years ago