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3 years ago

A trust is or is not one form of distributing an estate.

Mathematics

2 answers:

ss7ja [257]3 years ago

6 0

I believe it is one form of it.

mixas84 [53]3 years ago

3 0

Answer:

A trust is a form of distributing an estate.

Step-by-step explanation:

A trust is one form of distributing an estate.

A trust can be defined as any money, an estate or other property given to a person or institution for managing. It is also a form of holding property. To create a trust, the property owner transfers the legal ownership of his property to the trustee. This trustee will manage that property now for its beneficiaries.

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Jenna multiplied four numbers together and then divided by -2. The result was a positive value.

Juli2301 [7.4K]

Answer:

An odd number of factors were negative

Step-by-step explanation:

EXAMPLE: -3 × 4 × 8 × 2 = -192 then -192 ÷ -2 = 96

7 0

3 years ago

Read 2 more answers

A worker is paid $0.05 on the first day, $0.10 on the second day, $0.20 on the third day, $0.40 on the fourth day, and so on. Ho

Novay_Z [31]

This is a geometric sequence with a common ratio of 2

an = a1 * r^(n - 1)
n = term to find = 21
a1 = first term = 0.05
r = common ratio = 2
now we sub
a21 = 0.05 * 2^(21 - 1)
a21 = 0.05 * 2^20
a21 = 0.05 * 1048576
a21 = 52428.80 <==== after working 21 days

7 0

3 years ago

9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat

Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 2000, p = 1-0.995 = 0.005$

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

$P(X < 5) + P(X \geq 5) = 1$

We want $P(X \geq 5)$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044$

$P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445$

$P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235$

$P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480$

$P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765$

$P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710$

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0

3 years ago

George wants to know if two pieces of wire are the same length. one wire is 6/8 yard. the other is 3/4 yard. draw a number Line

wlad13 [49]

They are the same length. You need to find the common denominator (8) and multiply both the numerator and denominator on 3/4 to ger 6/8. Than, just draw a numberline comparing the lengths! Hope this helped

8 0

3 years ago

How the number e was discover

aalyn [17]

Dvzhrcvvxxn. Ik sorry

3 0

3 years ago

Read 2 more answers