In AABC, mZA = 32°, mZB = 25°, and a = 18. Find c to the nearest tenth.
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From an acceleration-time graph, you can work out the area under the graph to find the velocity. There are two triangles on the graph as shown below. The total area of the triangles are
Hence, the distance is 250×30=7500 ft
Hence, the distance is 250×30=7500 ft