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3 years ago

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The movement of both oxygen and carbon dioxide in the body is accomplished by ___.

1 answer:

ad-work [718]3 years ago

7 0

Answer: Diffusion

Explanation: Please give brainliest

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Which are functions of the endoplasmic reticulum (ER)?

Oksana_A [137]

Answer:

a. DNA storage

Explanation:

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3 years ago

Before collecting a specimen of urine or feces, the nursing assistant asks the nurse or consults the lab for?

bulgar [2K]

Before collecting a specimen of urine or feces, the nursing assistant asks the nurse or consults the lab for which storage and delivery method to use.

There are different tests that need to be performed on a urine or feces specimen. It depends on the patients that which test would be asked for him to be done.

The storage and delivery methods for urine and feces in the case of different tests has to be consulted by the nurse or consultant.

Incase of an emergency test, whose results are immediately required the method of delivery is a fast mode one. For patients that have a mild disease or are not at risk, other reliable methods can be used. Each specimen should be properly labeled for proper checking.

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2 years ago

A heavenly body in another's shadow is ____

Alex_Xolod [135]

<span>It is called a lunar eclipse</span>

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4 years ago

Read 2 more answers

1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.

Scilla [17]

1)The period of these ripples will be 0.2 sec.

2)The time period of sound wave will be 100 Hz.

3)The frequency of the sound wave will be 5×10⁶ Hz.

<h3>What is frequency?</h3>

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

Frequency of ripples (f₁)=5 Hz

The period of these ripples will be;

T₁=1/f₁

T₁=1/5

T₁=0.2 sec

The time period of sound wave (T)=0.01 seconds

The time period of sound wave;

f=1/T

f=1/0.01

f=100 Hz

Time period of A radio wave = 0.0000002 seconds

The frequency of the sound wave is;

f=1/T

f=1/0.0000002

f=5×10⁶ Hz

Hence,the period of these ripples will be 0.2 sec.

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3 years ago

A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be co

Naddika [18.5K]

Answer:

a = 45 m/s/s

Explanation:

As we know that total mass of the rocket is

$M = 6000 kg$

total mass of the fuel is given as

$m = 2000 kg$

all the fuel is burnt in 15 s

so rate of the fuel burning is given as

$\frac{dm}{dt} = \frac{2000}{15}$

$\frac{dm}{dt} = 133.33 kg/s$

now the thrust force on the rocket is given as

$F_{th} = v\frac{dm}{dt}$

$(6000 - 133.33 t) a = (900 + v)(133.33)$

so we have

$\frac{dv}{900 + v} = (133.33)\frac{dt}{6000 - 133.33 t}$

so we have

$ln(\frac{900 + v}{900}) = - ln(\frac{6000 - 133.3 t}{6000})$

$1 + \frac{v}{900} = \frac{6000}{6000 - 133.3 t}$

now acceleration is rate of change in velocity

$\frac{1}{900}\frac{dv}{dt} = \frac{133.3\times 6000}{(6000 - 133.3t)^2}$

so acceleration at t = 15 s

$a = 45 m/s^2$

3 0

4 years ago