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Deffense [45]
3 years ago
7

A sample that is treated exactly like the other experimental groups except that the variable is not applied to it is a(n) _____.

Physics
1 answer:
Arte-miy333 [17]3 years ago
7 0
This is a "control" - answer c).

You always need a control in an experiment, otherwise you don't know what influenced the changes. Imagine you make children eat more vegetables and they grow - do you know if it's due to vegetables or not? You need to have another group that eats normal amounts of vegetables to compare this. 
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Which statement best explains how tectonic activity affects long-term climate change?
Alina [70]

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The movement of continents changes wind patterns and ocean currents.

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Explanation:

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4 years ago
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Explain how magnets have an attractive force and repulsive force
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3 years ago
A ball has a diameter of 3.79 cm and average density of 0.0838 g/cm3.
suter [353]

Answer: 0.258 N

Explanation:

As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.

So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:

F = Fb – Fg

Fb= δH20* 4/3*π*(d/2)³  * g

Fg = δb* 4/3*π*(d/2)³ *g

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F= 0.258 N

3 0
4 years ago
1) A studious physics student is interrupted by a swarm of bees and chased off a cliff. Since she has her calculator in hand she
Nikolay [14]

Answer:

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8 0
3 years ago
How many heat is needed to melt 1.5kg of ice and then to raise the temperature of the resulting water 50 degree Celsius
BabaBlast [244]

Answer:

• The amount of heat required to melt ice and raise the temperature of water T^oCToC is

Q=mL_f+mc\Delta TQ=mLf+mcΔT

Here m=1.5 kgm=1.5kg

L_f=3.33*10^5 J/kgLf=3.33∗105J/kg is Latent heat of fusion of ice.

c=4186 J/kg.^oCc=4186J/kg.oC is heat capacity of water.

\Delta T=50 ^oC-0^oC=50^oCΔT=50oC−0oC=50oC

So,

Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 JQ=(1.50)[3.33∗105+(4186)(50)]=8.13∗105J

4 0
3 years ago
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