The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.
<h3>What is spring force?</h3>
The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =200
K is the spring constant= 2500 N/m
x is the length by which spring got stretched =?
The stretch of the spring is found as;
Hence the length by which the spring got stretched will be 0.08 m.
To learn more about the spring force refer to the link;
brainly.com/question/4291098
#SPJ4
Answer:
It refracts when it hits the glass.
Answer:
Explanation:
Given data
Speed of jet Vjet=1190 km/h
Speed of prop driven Vprop=595 km/h
Height of jet 7.5 km
Height of prop driven transport 3.8 km
Density of Air at height 10 km p7.8=0.53 kg/m³
Density of air at height 3.8 km p3.8=0.74 kg/m³
The drag force is given by:
The ratio between the drag force on the jet to the drag force on prop-driven transport is then given by:
Answer:
Minimize the elevation or jump distance
Explanation:
The only action that minimizes, the impact force is to reduce as much as possible the height of the jump, the dog, ie the height from the jump point of the building. Since at the time of the jump its speed will increase every second at the rate of 9 [m/ s], that is this low effect of the gravitational acceleration of 9 [m/s^2]
where:
vf = final velocity [m/s]
g = gravity [m/s^2]
h = elevation [m]
As we can see while there is higher height, at a higher speed will impact the ground.
Answer: The correct answer is option b.
Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.
The acceleration of the rocket is 
To calculate the distance of rocket, we use third equation of motion, which is:
where, v = final velocity = 445m/s
u = initial velocity = 0m/s
a = acceleration = 
s = distance = ? m
Putting values in above equation, we get:
