Answer:
254.47 
Step-by-step explanation:
First you have to know the formula for the area of a circle which is:
<h2>
</h2>
In the word problem it gives us the radius of a pancake which is 9 cm, so we just need to plug it into<em> r </em>in our formula:
<h2>
</h2><h2>
</h2>
≈ 254.47
Answer: A. 21,120
Step-by-step explanation: Good luck! :D
bearing in mind that 4¾ is simply 4.75.
![\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$600\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=600\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies A=600(1.05)^3\implies A=694.575 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%5C%24600%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20n%3D%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%20%5Ctextit%7Bannually%2C%20thus%20once%7D%20%5Cend%7Barray%7D%5Cdotfill%20%261%5C%5C%20t%3Dyears%5Cdotfill%20%263%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D600%5Cleft%281%2B%5Cfrac%7B0.05%7D%7B1%7D%5Cright%29%5E%7B1%5Ccdot%203%7D%5Cimplies%20A%3D600%281.05%29%5E3%5Cimplies%20A%3D694.575%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
well, the interest for each is simply A - P
695.575 - 600 = 95.575.
862.032 - 750 = 112.032.
The number of zeros of the quadratic functions, considering their discriminant, is given as follows:
- discriminant = 0: 1 Real number solution.
- discriminant = -36: 0 Real number solutions.
- discriminant = 3: 2 Real number solutions.
- discriminant = 2: 2 Real number solutions.
- discriminant = 100: 2 Real number solutions.
- discriminant = -4: 0 Real number solutions.
<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>
A quadratic equation is modeled by:
The discriminant is:
The solutions are as follows:
- If
, it has 2 real solutions.
- If
, it has 1 real solutions.
- If
, it has 0 real solutions.
Hence, for the given values of the discriminant, we have that:
- discriminant = 0: 1 Real number solution.
- discriminant = -36: 0 Real number solutions.
- discriminant = 3: 2 Real number solutions.
- discriminant = 2: 2 Real number solutions.
- discriminant = 100: 2 Real number solutions.
- discriminant = -4: 0 Real number solutions.
More can be learned about quadratic functions at brainly.com/question/24737967
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