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Irina-Kira [14]
3 years ago
5

If the sum of two prime numbers is divisible by seven and is a perfect square what is the possible product of these numbers

Mathematics
1 answer:
disa [49]3 years ago
3 0
The possible product can be 94.
You need the sum of two prime numbers that is divisible by seven and is a perfect square.
A number that is a perfect square and divisible by 7 is number 49 (7^2=49).
A prime number is a number that is divisible only by 1 and itself.
49 = 47 + 2 (47 and 2 are prime)
47 × 2 = 94.
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The area of a rectangle is 66 ft^2:

L * W = 66

Length of the rectangle is 7 feet less than three times the width:

L = 3W-7

Substitute L in terms of W:

(3W-7) * W = 66

Factorise the equation:

3W^2 -7W = 66

3W^2 - 7W - 66 = 0

Factors of 66 =

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(3W + 11) (W - 6) = 0

Solve for W:

3W + 11 = 0

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W = 0 + 6

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L = 3(6)-7

L = 18-7

L = 11

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11 * 6 = 66

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