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Tamiku [17]
3 years ago
5

Write its IUPAC name?​

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

Hello

please make sure that there is any group which is join with alkane

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The process, when an atom gains electrons is called
max2010maxim [7]

Answer:

When an atom gains/loses an electron, the atom becomes charged, and is called an ion. Gaining an electron results in a negative charge, so the atom is an anion. Losing an electron results in a positive charge, so atom ion is a cation

Explanation:

Answerd the question : ion

8 0
3 years ago
Brass is stronger than steel<br> True or False
Ket [755]
False . Steel is stronger
8 0
3 years ago
Can you help me pretty please !!!
Vika [28.1K]
The answer is A it depends on the distance
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5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
Korolek [52]

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

<h3>What is a limiting reactant?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid CH_3CO_2H  reacts with baking soda NaHCO_3 according to the equation:

CH_3CO_2H  + NaHCO_3 → CH_3CO_2Na + CO_2 + H_2O

1. Molar mass of NaHCO_3 is 23+1+12+16×3 = 84 g/mol

= \frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}

= \frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}

=0.29 mol NaHCO_3

2. From the balanced equation we see that 1 mole of NaHCO_3 reacts with 1 mole of CH_3CO_2H , then 0.29 moles of NaHCO_3 react with 0.29 moles of CH_3CO_2H.

3. Mass of 1 mole of CH_3CO_2H is 12+ 1×3+12+16×2=60 g/mol

= \frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}

=17.4 g CH_3CO_2H

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g CH_3CO_2H is very close to 17.4 g CH_3CO_2H. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

Learn more about the limiting reactant here:

brainly.com/question/19654705

#SPJ1

4 0
2 years ago
How do the valence electrons of an element determine how they will combine with other elements to produce a compound? Please hel
Vlad1618 [11]

Answer:

See explanation

Explanation:

The valence electrons are electrons found on the valence (outermost) shell of an atom.

When an atoms form compounds, there is an exchange of valence electrons between the atoms of one element and the atoms of another element.

Let us consider a typical example, sodium has one valence electron and chlorine has seven valence electrons. This means that chlorine needs one electron to complete its octet while sodium needs to release one electron in order to attain the octet structure.

So, sodium gives out its one electron and becomes a stable sodium ion and chlorine accepts that electron and becomes a stable chloride ion. This is how the compound sodium chloride is formed.

8 0
3 years ago
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