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3 years ago

Help 4 me???? ples????

Chemistry

2 answers:

Ainat [17]3 years ago

4 0

I think it’s the second one

frutty [35]3 years ago

3 0

Answer:

its the first one.

Explanation:

If sodium loses an electron, it now has 11 protons, 11 neutrons, and only 10 electrons, leaving it with an overall charge of +1

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The oxidation of sulfur dioxide by oxygen to sulfur trioxide has been implicated as an important step in the formation of acid r

Igoryamba

Answer:

The value of the equilibrium constant $K_p$ at this temperature is 3.42.

Explanation:

Partial pressure of the sulfur dioxide = $p_1=0.564 atm$

Partial pressure of the oxygen gas = $p_2=0.102 atm$

Partial pressure of the sulfur trioxide = $p_3=0.333$

$2 SO_2(g) + O_2(g)\rightleftharpoons 2 SO_3(g)$

The expression of an equilibrium constant is given by :

$K_p=\frac{(p_3)^2}{(p_1)^2\times p_2}$

$K_p=\frac{(0.333 atm)^2}{(0.564 atm)\times (0.102 atm)}=3.42$

The value of the equilibrium constant $K_p$ at this temperature is 3.42.

7 0

4 years ago

A major component of gasoline is octane. When liquid octane is burned in air it reacts with oxygen gas to produce carbon dioxide

irakobra [83]

Answer:

0.267 mol

Explanation:

The unbalanced equation for the reaction that takes place is:

C₈H₁₈ + O₂ → H₂O + CO₂

Once we balance it we're left with:

2C₈H₁₈ + 25O₂ → 18H₂O + 16CO₂

Using the stoichiometric ratio of water and octane from the balanced reaction, we can convert mol of water into mol of octane:

2.40 mol H₂O * $\frac{2molC_8H_{18}}{18molH_2O}$ = 0.267 mol C₈H₁₈

Thus 0.267 moles of octane are needed to produce 2.40 mol of water.

5 0

3 years ago

Name the following bases -Ba(OH)2 - Ca(OH)2 -RbOH

Harman [31]

$Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}$

$Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}$

$RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}$

3 0

3 years ago

Read 2 more answers

A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.

erastovalidia [21]

The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)

4 0

3 years ago

What is the osmolarity of .00001 grams (0.1 mg%) of ethanol (does not dissociate) in one liter?

MrMuchimi

Explanation:

As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.

As, molar mass of ethanol = 46.07 g/mol

Therefore, no. of moles of ethanol will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.00001 g}{46.07 g/mol}$

= $2.17 \times 10^{-7}$ mol

As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{2.17 \times 10^{-7} mol}{1 L}$

= $2.17 \times 10^{-7}$ mol/L

Since, for the given solution Molarity = osmolarity

Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol in 1 L is $2.17 \times 10^{-7}$ osmol/L.

8 0

3 years ago