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2 years ago

At 27.00 °c a gas has a volume of 6.00 L . What will the volume be at 150.0 °c

1 answer:

3 0

T₁ = 27°C = 27 + 273 = 300K, V₁ = 6 L,

T₂ = 150°C = 150 + 273 = 423K, V₂ = ?,

By Charles' Law: V₁/T₁= V₂/T₂

6/300 = V₂/423

423*(6/300) = V₂

8.46 = V₂

Volume at 150°C =8.46 L.

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Explanation:

The heat released by the reaction is absorbed by the calorimeter and the solution.

The chemical equation used to calculate the heat released follows:

$q=c\times \Delta T$

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c = heat capacity of calorimeter = 1620 J/K

$\Delta T$ = change in temperature = $0.150^oC=0.150K$ (Change remains same)

Putting values in above equation, we get:

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When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

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We are given:

Moles of monoclinic sulfur = 1 mole

To calculate the enthalpy change of the reaction, we use the equation:

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q = amount of heat released = -243 J

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Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{-243J}{1mol}=-243J/mol$

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Seedless vascular plants brainly.com/question/6047633

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