3. Answer: a) RT
b) XZ
c) TS
4. Answer: a) 26
b) 58
c) 21.5
d) 127
<u>Step-by-step explanation:</u>
2(PT) = AE 2(CP) = AN 2(CT) = EN
2(13) = AE 2(29) = AN 2(CT) = 43
26 = AE 58 = AN CT = 21.5
Perimeter = AE + AN + EN
= 26 + 58 + 43
= 127
c = circumference
pi = 3.14
r = radius = 9 inches
d = diameter
c=pi*d
The radius is half of the diameter, d = 2r. Then d = 2*9=18.
plug into equation. c= pi*d = 3.14*18
round accordingly and you may want to include that the measurement you end up with is in inches.
Answer:
x
Step-by-step explanation:
f(x) = (x-1)/3
g(x) = 3x+1
f(x) °g(x) =
Substitute g(x) in for x in the function f(x)
f(x) °g(x) = (g(x) -1)/3
= (3x+1 -1)/3
= 3x /3
=x
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
