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3 years ago

recurring decimals to fractions and give Convert the following she answer a simplest form 0•28 when 8 is recurring

Mathematics

1 answer:

Ahat [919]3 years ago

3 0

Answer:

13/45

Step-by-step explanation:

x = .2888888888

100(x + .2888888)

100x + 28.8888

10x + 2.88888

90x = 26

x = 26/90 = 13/45

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Find the lengths of "x"

yanalaym [24]

Using pythagorean's theorem
a^2+b^2=c^2

a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2

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3 years ago

Higher order thinking: Jeff finds some bugs. He finds 10 Fewer grasshoppers than crickets. He finds 5 fewer crickets than Lady b

Stells [14]

C - 10 = g
L - 5 = C

g = 5

then altogether he finds

40 bugs

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3 years ago

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Can you find the area for this?

Tanzania [10]

Answer:

b. is the right answer of your question

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The Country Buffet restaurant has tables that seat 6 people and booths that can seat 4 people. The restaurant has 38 seating uni

Alina [70]

Answer:

There are 20 booths and (38 - 20), or 18, tables

Step-by-step explanation:

Represent the number of tables with t and the number of booths with b.

We need to find the values of t and b.

(6 people/table)(t) + (4 people/booth)b = 188 (units are "people")

t + b = 38 (units are "seating units")

Solving the second equation for t, we get 38 - b = t.

Substitute 38 - b for t in the first equation:

(6 people/table)(38 - b) + (4 people/booth)b = 188

Then solve for b: 6(38) - 6b + 4b = 188, or:

228 - 2b = 188, or 2b = 228 - 188, or 2b = 40. Thus, b = 20 (booths)

There are 20 booths and (38 - 20), or 18, tables.

6 0

3 years ago

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

5 0

3 years ago

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recurring decimals to fractions and give Convert the following she answer a simplest form 0•28 when 8 is recurring​

recurring decimals to fractions and give Convert the following she answer a simplest form 0•28 when 8 is recurring