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2 years ago

Which of these sets of ordered pairs are functions?

Mathematics

1 answer:

Arisa [49]2 years ago

4 0

Answer: The second one if im wrong please dont get maddd :(

but 80% im ure its right

Step-by-step explanation:

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Determine which of the lines, if any, are parallel or perpendicular. Explain.

hodyreva [135]

Answer:
line a and b are parallel
line c is not perpendicular because it is not 3

step-by-step explanation:
if the slope is the same it is parallel
if the slope is the complete opposite it is perpendicular
lines a and b are parallel with a slope of -1/3
(0, 5) (3, 4)
m = 4 - 5 / 3 - 0
m = -1 / 3
m = -1/3
(-1, 1) (2, 0)
m = 0 - 1 / 2 + 1
m = -1 / 3
m = -1/3
line c is perpendicular to lines a and b the slope is
(0, 0) (2, 5)
m = 5 - 0 / 2 - 0
m = 5/2
2.5

8 0

3 years ago

What is the simplify of this expression -2(2b-3)

patriot [66]

-2(2b-3)

Multiply the bracket by -2

Whenever multiplying a -negative number with a -negative number= + positive number.

(-2)(2b)(-2)(-3)

-4b+6

Answer: -4b+6

6 0

3 years ago

Read 2 more answers

What is the surface area of the prism?

Harman [31]

Area of lower rect + area of upper + 4 * sides rect areas

lower = upper rect

2 * rect1 + 4 * rect2

Area = 2 * 6 * 11 + 2 * 11 * 9 + 2 * 9 * 6 = 438 ft^2

or simply just take 2 ( and multiply each two sides.

5 0

3 years ago

I need help with this question

Black_prince [1.1K]

Answer:

Step-by-step explanation:

The slope-intercept form is found by solving that equation for y.

If $y-3=\frac{1}{2}(x-1)$ then

$y-3=\frac{1}{2}x-\frac{1}{2}$ and

$y=\frac{1}{2}x-\frac{1}{2}+3$ and

$y=\frac{1}{2}x-\frac{1}{2}+\frac{6}{2}$ so

$y=\frac{1}{2}x+\frac{5}{2}$

The answer you have chosen is the correct one! Good job!

6 0

2 years ago

which graph represents the solution set of the system of inequalities? (is my selected answer correct, if not please help!!)

algol [13]

Answer:

the graph on the right-top

Step-by-step explanation:

Transferring an "x" to the right side in $x+y\ge-3$ , we get $y\ge -x-3$

The system of inequalities is

$\left \{ {{y$

We have y=2x+2 - ascending function with a=2, b=2

b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.

y=-x-3 - descending function with a=-1, b=-3

y<2x+2 is an area below the ascending function and we see that on the left-

$y\ge-x-3$ is an area above the descending function

On the left-down we have an area above both functions, so we refuse this picture

Right-top is correct

7 0

3 years ago