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GalinKa [24]
3 years ago
13

Please help! The question is in the image

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

BC = 3

Step-by-step explanation:

If B is the midpoint of AD, that means AB = BD

AD = 12 so BD = 1/2 of AD  and BD = 6

If C is the midpoint of BD, that means BC = CD

BD = 6 so BC = 1/2 of BD  and BC = 3

Goshia [24]3 years ago
3 0

Answer:

I am pretty sure that your answer would be 3.

Step-by-step explanation:

The reason why is because if B if half of line segment AD and AD is equal to 12, then B must be equal to 6 since half of 12 is 6. Next, since C is the mid-point for line segment BD then C must be 3 since half of 6 is 3. And finally, that means line segment BC is three since it is 1/2 of BD.

Hope this helps! :)

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What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
Round 5.242 to the nearest TENTH
Alex787 [66]
5.242 to the nearest tenth is 5.2.
6.537 to the nearest tenth is 6.5.
11.382 to the nearest tenth is 11.4.
8 0
3 years ago
Read 2 more answers
The simplest form of the expression 4m-17/m^2-16 + 3m-11/m^2-16 has ____in the numerator and___ in the denominator.
lara31 [8.8K]
For this case we have the following expression:
 \frac{4m-17}{m^2-16} + \frac{3m-11}{m^2-16}
 Since the denominator is equal, then we can add the numerator.
 We have then:
 \frac{(4m-17) + (3m-11)}{m^2-16}
 Adding similar terms we have:
 \frac{(4m+3m) + (-17-11)}{m^2-16}
 Rewriting we have:
 \frac{7m - 28}{m^2-16}
 Doing common factor in the numerator we have:
 \frac{7(m - 4)}{m^2-16}
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 Answer:
 
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3 0
3 years ago
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blagie [28]
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8 0
3 years ago
The Director of Admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall sem
VMariaS [17]

Answer:

Variance = 24900

Standard Deviation = 157.7973        

Step-by-step explanation:

We are given the following in the question:

Number of admissions:    1000     1200    1500

Admissions Probability:     0.6        0.3       0.1

Formula:

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Variance =

\sigma^2 = E(x^2) - (E(x))^2\\\sigma^2 = 1257000 -(1110)^2\\\sigma^2 =24900

Thus, the variance is 24900.

Standard Deviation =

\sigma = \sqrt{\sigma^2} = \sqrt{24900} = 157.7973

Thus, the standard deviation is 157.7973

7 0
3 years ago
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