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2 years ago

Determine the quadrant(s) in which (x, y) could be located. (Select all that apply.)

Mathematics

1 answer:

Eva8 [605]2 years ago

8 0

None of these because they all are 0

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The area of a triangle is 22 yd with a base of 8 years. What is the height, in yards?

cluponka [151]

The area of a triangle can be found using the formula 1/2*b*h

We can substitute what we know in now, 22 = 1/2*8*h

22 = 4*h
22 = 4*5.5

The answer would be 5.5 yards

I hope this helps!

6 0

3 years ago

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Find volume of sphere in cubic yards whose radius is 5 yard<br><br> Use pi = 3.14

enyata [817]

Answer:

523.333 cubic yards

Step-by-step explanation:

The formula for the volume of a sphere is $\frac{4}{3}\pi r^{3}$ where $r$ is the radius.

The radius of the given sphere is $r=5$ yards and $\pi =3.14$ .

Therefore, we can substitute in the radius and solve:

$V_{sphere}= \frac{4}{3}\*\times3.14\times 5^{3} =523.333$ cubic yards

4 0

1 year ago

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If a pool holds 22,000 gallons, how long will it take to fill the pool at a rate of 400 gallons per minute, rounded off to the n

nalin [4]

400x=22,000

22,000/400=x

55=x Hopefully this is right, and hopefully this helps

8 0

2 years ago

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Please help i put brainliest

valkas [14]

Answer:

Step-by-step explanation:

x 12x - 6 3x + 3 6(2x - 1)

1 6 6 6

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2 years ago

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

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2 years ago