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sladkih [1.3K]
3 years ago
7

A force gives a 5.0 kg object an acceleration of 2.0 m/s 2. The same force would give a 20 kg object an acceleration of _____. 0

.5 m/s 2 2.0 m/s 2 4.9 m/s 2 8.0 m/s 2
Physics
2 answers:
belka [17]3 years ago
8 0

Answer:

The acceleration of the object is 0.5 m/s²

a is correct.

Explanation:

Given that,

Mass of object = 5.0 kg

Acceleration a = 2.0 m/s^2

Using newton's second law

The force is the product of the mass of the object and acceleration.

F = ma

Put the value of m and a

F = 5.0\times2.0

F = 10\ N

Now, The same force would give a 20 kg object

So, Using newton's second law again

F = ma

The acceleration is

a =\dfrac{F}{m}

Put the value of m and F

a = \dfrac{10}{20}

a =0.5 m/s^2

Hence, The acceleration of the object is 0.5 m/s²

Oksi-84 [34.3K]3 years ago
6 0

m = 5 kg

a = 2 m/s²

to find the force that accelerates the 4 kg object @ 2 m/s²

F = ma = 5 kg x 2 m/s² = 10 N

To find what acceleration 10 N would give a 20 kg object

a = F/m = 10 N/20 kg = 0.5 m/s

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# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah
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Answer:

<h2>10 \: m/s ^2</h2><h2 />

Explanation:

Solution,

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We have to convert 72 km /h in m/s

72 \: km \: per \: hour

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Now,

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7 0
3 years ago
A bucket of mass m is hanging from the free end of a rope whose other end is wrapped around a drum (radius R, mass M) that can r
mr Goodwill [35]

Answer:

Explanation:

Let T be the tension .

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mg - T = ma

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TR = Iα

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T =  Ia/ R²

Replacing this value of T in the other equation

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mg =  Ia/ R² +ma

a ( I/ R² +m)= mg

a = mg / ( I/ R² +m)

mg - T = ma

mg - ma  = T

mg - m x mg / ( I/ R² +m) = T

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7 0
3 years ago
As a pole of a 2nd-order discrete-time system moves away from the origin in the z-plane, while its phase remains constant, the d
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Answer:

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As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.

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