Answer:
0.66 degrees
Explanation:
The computation of the angle of the third dark interference is shown below:
The condition of the minima is
Path difference = (2n +1) ×
÷ 2
For third minima, n = 2
Now
xd ÷ D = (2 × 2 + 1) ×
÷ 2
d tan Q_3 = 5
÷ 2
tan Q_3 = 5
÷ 2d
Q_3 = tan^-1 × (5
÷2d)
= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)
= 0.66 degrees
Answer:
R = 2481 Ω
L= 1.67 H
Explanation:
(a) We have an inductor L which has an internal resistance of R. The inductor is connected to a battery with an emf of E = 12.0 V. So this circuit is equivalent to a simple RL circuit. It is given that the current is 4.86 mA at 0.725 ms after the connection is completed and is 6.45 mA after a long time. First we need to find the resistance of the inductor. The current flowing in an RL circuit is given by
i = E/R(1 -e^(-R/L)*t) (1)
at t --> ∞ the current is the maximum, that is,
i_max = E/R
solve for R and substitute to get,
R= E/i_max
R = 2481 Ω
(b) To find the inductance we will use i(t = 0.940 ms) = 4.86 mA, solve (1) for L as,
Rt/L = - In (1 - i/i_max
)
Or,
L = - Rt/In (1 - i/i_max
)
substitute with the givens to get,
L = -(2481 Si) (9.40 x 10-4 s)/ In (1 - 4.86/6.45
)
L= 1.67 H
<u><em>note :</em></u>
<u><em>error maybe in calculation but method is correct</em></u>
6. "The electric field caused by an electron is weakest near the electron" is FALSE.
7. "An electric field becomes weaker as distance from the electron increase" is TRUE.
<u>Explanation:</u>
The "electrical field" covers the electrical charge and exerts, attracts or repels other charges in the field.The electric field caused by an electron is strongest near the electron while it become weak as distance from the electron increase.
The reason behind is, at a point the direction of the field line is at that point the direction of the field. The relative magnitude of the electric field will be proportional to the field line density. The field is strongest where the field lines are near together and when the field lines are at increasing distance the field is weakest.
<h2>
Electric field at the location of the charge is 169.97 N/C</h2>
Explanation:
Electric field is the ratio of force and charge.
Force, F = 6 x 10⁻⁶ N
Charge, q = 3.53 x 10⁻⁸ C
We have

Electric field at the location of the charge is 169.97 N/C