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wolverine [178]
3 years ago
11

Find the measure of each interior angle for a regular triangle. round to the nearest tenth if nessessary

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

24

54

87

65

Step-by-step explanation:

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Find the mid segment of GH
noname [10]

Answer:

B. 2

Step-by-step explanation:

Based on the Midsegment of a trapezoid theorem:

GH = (BC + FE)/2

9x - 3 = (19 + (5x + 1))/2) (substitution)

9x - 3 = (20 + 5x)/2

Cross multiply

2(9x - 3) = 20 + 5x

18x - 6 = 20 + 5x

Collect like terms

18x - 5x = 20 + 6

13x = 26

Divide both sides by 13

x = 26/13

x = 2

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3 years ago
Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0
3 years ago
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