The chemical equation needs to be balanced so that it follows the law of conservation of mass.
Answer:
Mass of iron = 59.375 gm
Explanation:
Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C
The water gains:
4.18 j/g-C * 50 * (40-30 C) = 2090 j
The steel gave up 2090 j going from 120 to 40 C
2090 = .44 j/g-C * m * (120-40) solve fro m = 59.375 gm
Answer: 1. CaO + H2O => Ca(OH)2
2. P4 + 5O2 => 2P2O5
3. 2 Ca + O2 => 2 CaO
4. 8 Cu + S8 => 8 CuS
5. CaO + H2O => Ca(OH)2
6. S8 + 8 O2 => 8 SO2
7. 3 H2 + N2 => 2 NH3
8. H2 + Cl2 =>2 HCl
9. 16 Ag + S8 => 8 Ag2S
10. Cr + O2 => 2Cr2O3
11. 2Al + 3Br2 => 2AlBr3
12. 2Na + I2 => 2NaI
13. 2H2 + O2 =>2 H2O
14. 4 Al + 3O2 => 2 Al2O3
Explanation: