Answer:
400 K
Explanation:
Charles's law states:
A determined volume of a gas is directly proportional to its temperature, while we have constant pressure.
V₁ / T₁ = V₂ / T₂
We replace data:
5 L / 100K = 20L / T₂
T₂ = 20L . 100K / 5 L
T₂ = 400 K
The volume was quadrupled, so the temperature did.
If we want T° at Celsius degree:
400 K - 273 = 127°C
Answer:
121.37 moles.
Explanation:
Always one mole of any molecule contains Avogadro number of molecules.
So one mole of methane contains 6.023*10^23 molecules.
Now we need number of moles of methane in 7.31*10^25 molecules.
This is just cross multiplication stuff.
6.023*10^23 molecules —————- 1 mole
7.31*10^25 molecules ——————- ?
= (7.31*10^25) / (6.023*10^23)
= 121.37 moles.
Answer:
1 = Q = 7315 j
2 =Q = -21937.5 j
Explanation:
Given data:
Mass of water = 50 g
Initial temperature = 20°C
Final temperature = 55°C
Energy required to change the temperature = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 j/g.°C.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 55°C - 20°C
ΔT = 35°C
Q = 50 g× 4.18 j/g.°C×35°C
Q = 7315 j
Q 2:
Given data:
Mass of metal = 100 g
Initial temperature = 1000°C
Final temperature = 25°C
Energy released = ?
Specific heat capacity = 0.225 j/g.°C
Solution:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 25°C - 1000°C
ΔT = -975°C
Now we will put the values in formula.
Q = 100 g × 0.225 j/g.°C × -975°C
Q = -21937.5 j
Negative sign show that energy is released.
