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9 months ago

What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol

Chemistry

1 answer:

ad-work [718]9 months ago

7 0

Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

molarity = moles of NaCl/(volume of solution)

molarity = 1.078 moles/(0.65 L)

molarity = 1.66 M

Answer: the molarity of the solution is 1.66 M.

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You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions

artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0

3 years ago

1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium

aniked [119]

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

$M_1$ =concentration of stock solution = 0.150 mol/L

$V_1$ = volume of stock solution = 10.0 ml

$M_2$ = concentration of dilute solution = ?

$V_2$ = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

$0.150\times 10.0=M_2\times 100.0$

$M_2=0.015mol/L$

As the concentration is less than the original concentration, the solution is termed as dilute.

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2 years ago

Can someone help.? thanks :)

laila [671]

Answer:

1. Equation: 2x + 3 = 9x - 11

2. Each row has 2 chairs

Explanation:

The variable x represents the number of chairs in each row.

1. She can form 2 rows of a given length with 3 chairs left over.

Thus, she has:

number of rows number of chairs in chairs number of chairs

each row left over she has

2 x 3 2x + 3

2. She can form 9 rows of the same length if she gets 11 more chairs.

That means that she is short in 11 chairs to have 9x chairs, or that she has 11 less chairs than 9x chairs. Then she has:

9x - 11

3. Equation:

Then, number of chairs she has is 2x + 3 and, also, 9x - 11, which allows to set the equation:

2x + 3 = 9x -11

4. Solve the equation:

9x - 2x = 3 + 11

7x = 14

x = 2

Therefore, each row has 2 chairs, and she has 2x + 3 = 4 + 3 = 7 chairs.

4 0

3 years ago

What is a number bond.

GenaCL600 [577]

Explanation:

number bonds are pairs of numbers that can be added together to make another number e.g. 4 + 6 = 10. They are some of the most basic and most importantparts ofmaths for children to learn

3 0

2 years ago

A 25.0g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is dropped into an insulated container containin

Angelina_Jolie [31]

Answer:

The equilibrium temperature of water is 25.6 °C

Explanation:

Step 1: Data given

Mass of the sample of brass = 25.0 grams

The specific heat capacity = 0.375 J/g°C

Mass of water = 250.0 grams

Temperature of water = 25.0 °C

The initial temperature of the brass is 96.7°C

Step 2: Calculate the equilibrium temperature

Heat lost = heat gained

Q(sample) = -Q(water)

Q = m*C* ΔT

m(sample)*c(sample)*ΔT(sample) = - m(water)*c(water)*ΔT(water)

⇒m(sample) = the mass of the sample of brass = 25.0 grams

⇒with c(sample) =The specific heat capacity = 0.375 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 =T2 - 96.7 °C

⇒with m(water) = the mass of the water = 250.0 grams

⇒with c(water) = the specific heat capacity = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = T2 - 25.0°C

25.0 * 0.375 * (T2 - 96.7) = - 250.0 * 4.184 J/g°C * (T2 - 25.0°C)

9.375T2 - 906.56 = -1046T2 + 26150

9.375T2 + 1046T2 = 26150 + 906.56

1055.375T2 = 27056.26

T2 = 25.6 °C

The equilibrium temperature of water is 25.6 °C

4 0

3 years ago