Question

Hello! Please help thanks

Answer 1

Answer:

A. $\frac{5}{13}$

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is $\frac{opposite}{hypotenuse}$

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be $\frac{PR}{PQ}$

Substituting the values of PR and PQ gives sin(Q) as $\frac{5}{13}$, which is A

Hope this helps!