Hello! Please help thanks
1 answer:
Answer:
A.
Step-by-step explanation:
Hi there!
We are given right triangle PQR, with PR=5, RQ=12, and PQ=13
We want to find the value of sin(Q)
Let's first recall that sine is
In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse
So that means that sin(Q) would be
Substituting the values of PR and PQ gives sin(Q) as , which is A
Hope this helps!
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Answer:
<h2>Y=1/2x-1</h2>Find where the expression
1/2x−1 is undefined.
x=1/2
Consider the rational function
R(x)=ax^n/bx^m where n is the degree of the numerator and m is the degree of the denominator.
1. If n<m, then the x-axis, y=0, is the horizontal asymptote.
2. If n=m, then the horizontal asymptote is the line y = ab.
3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).
Find n and m.n=0m=1
Since n<m, the x-axis, y=0, is the horizontal asymptote.y=0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x=1/2
Horizontal Asymptotes:
y=0
No Oblique Asymptotes
<h2>2x+y=4</h2>Subtract 2x from both sides of the equation.
y=4−2x
Rewrite in slope-intercept form.
The slope-intercept form is
y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Reorder 4 and −2x.
y=−2x+4
Use the slope-intercept form to find the slope and y-intercept.
Find the values of m and b using the form
y=mx+b.
m= - 2b=4
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −2
y-intercept: (0,4)
Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y
values.
Find the x-intercept.
x-intercept(s):
(2,0)
Find the y-intercept.
y-intercept(s):
(0,4)
Create a table of the x and y values.
x y
0 4
2 0
Graph the line using the slope and the y-intercept, or the points.
Slope: −2
y-intercept:
(0,4)
Step-by-step explanation:
Hope it is helpful...
