Answer:
s(r(2)) = 6
Step-by-step explanation:
You would first solve for r(2). You then input r(2) which equals -2 into s(r(2)).
r(x)= -2x + 2
r(2)= -2(2) + 2
r(2)= -4 +2
r(2)= -2
s(x)=x² + 2
s(r(2)) = (-2)² +2
s(r(2)) = 6
Slope is known as rise over run. Because the line is pointing "\", it is negative.
The rise, the distance from one point to another, specifically from (0,4) to (1,1) is 3, as 4-1=3. your run is 1-0=1.
So your rise over run is -3/1 or, -3.
Your y-int is where when x=0, y=?
In this case y=4 when x=0.
Your equation is
y=-3x+4
Answer:
A.
{-4 ≤ x ≤ 4}
{-4 ≤ y ≤ 4}
Step-by-step explanation:
We’ll domain is the amount of x values,
Range is the amount of y values
_______________________________
Domain:
Starts from -4 to 4
{-4 ≤ x ≤ 4}
I made the sign less than or equal to because the circle lines are solid.
Range:
This starts from -4 to 4 also.
{-4 ≤ y ≤ 4}
<em>Thus,</em>
<em>answer choices A. is correct</em>
<em />
<em>Hope this helps :)</em>
Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
