1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
topjm [15]
3 years ago
15

4. A company manufactures tires to meet the annual demand of 125,000 production runs. One production run involves producing 100

tires. To produce the tires involves a set up cost of T.Sh 600 for general maintenance and operating time. The annual holding cost per tire is Tsh 24 if the companies manages an inventory of tires in order to stabilize production process, determine a) The number of tires that must be manufactured routinely at the least cost b) What is the minimum total inventory cost?
Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

a) Economic order or production quantity = 2,500 tires.

Number of production runs in a year = 50 runs

Hence, 2,500 tires should be produced in each of the 50 runs in a year to minimize total cost.

b) Minimum total inventory cost = Tsh 30,000

Step-by-step explanation:

The total cost for the tire production firm will be a sum of the total production cost and total inventory cost.

Total cost = Total Production cost + Total inventory cost

Total Production Cost = (Number of production runs in a year) × (Setup Cost of one production run)

Number of production runs in a year = (Annual demand)/(Number of units produced per production run)

Let the annual demand = D

Number of units produced per production run = Q

Setup Cost of one production run = S

Number of production runs in a year = (D/Q)

Total Production Cost = (DS/Q)

Total inventory Cost = (Average inventory level) × (Cost of holding 1 unit in inventory)

Average inventory level is usually assumed to be half of the number of units in a production run = (Q/2)

Cost of Holding a unit of product in inventory = H

Total inventory Cost = (QH/2)

Total cost = TC = (DS/Q) + (QH/2)

At minimum cost, (dTC/dQ) = 0

(dTC/dQ) = -(DS/Q²) + (H/2) = 0

(DS/Q²) = (H/2)

Q² = (2DS/H)

Hence,

Economic order/production quantity = Q = √(2DS/H)

For this question

D = Annual demand = 125,000 tires

S = Setup cost for one production run = Tsh 600

H = Holding cost for one unit in inventory = Tsh 24

Q = √(2×125000×600/24) = 2,500 units

Number of production runs in a year = (D/Q) = (125000/2500) = 50 production runs.

b) Total Inventory Cost = (QH/2)

At minimum total inventory cost, Q = 2,500

Minimum total inventory cost = (2500×24/2) = Tsh 30,000

Hope this Helps!!!

You might be interested in
You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second
natta225 [31]
To find the total probability, we first need to solve for the probability of the individual events.

Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T 


Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)

The possibility of both events...

P(consonant then 'e')=7/11*3/10=21/110

Answer: P=21/110
6 0
3 years ago
Somebody can help me plz? It seems easy for y’all but not for me haha
Naddika [18.5K]

Answer:

I'll say 25 but not too sure!

3 0
3 years ago
A rental car company charges $31.91 per day to rent a car and $0.07 for every mile driven. Hudson wants to rent a car, knowing t
qaws [65]

The inequality that can be used to determine x is 31.91x + 7 \leq 70

<u />

<h3>How to generate the inequality</h3>

<u>Given data</u>

Rental company charge per day = $31.91

Rental company charge per mile driven = $0.07

Hudson  plans to drive 100 miles

Hudson has at most $70

solution

let x represent he maximum number of days Hudson can afford to rent while staying on budget. cost of number of days is:

$31.91 * x= 31.91x

As Hudson plans to ride 100 miles; cost is:

100 * 0.07 = $7

therefore number of days plus 100 miles ride is:

31.91x + 7

with a limit of less than or equal to the budget we have:

31.91x + 7 \leq 70

The inequality above could be used to determine x

Read more on inequality here:  brainly.com/question/11613554

#SPJ1

6 0
1 year ago
5.7x10^6 as an ordinary number​
Andrew [12]

Answer:

5700000

Step-by-step explanation:

8 0
2 years ago
A^8/a^3 <br> hey can someone help me
Stells [14]
A^8/a^3=a^5 you subtract the exponents
3 0
3 years ago
Other questions:
  • There are 20 pens in a package. Ten of the pens are black, 8 are blue, and the rest are red.
    13·1 answer
  • (5i^{2} -3) * (6i *2^{6})
    14·1 answer
  • A cola company decides to test five different brands of soft drink. The different brands have been labeled F, G, H, I, and J. Th
    11·1 answer
  • Please help!! dont answer if you're not going to explain! need help with my geometry!
    6·1 answer
  • How to describe a transformation?
    11·1 answer
  • To date, Ty has cumulative earnings of $107,600. This week he is paid $3,000. What's the total amount of social security tax for
    14·2 answers
  • What is the property of addition that is illustrated by the equation 0+34=34?
    9·1 answer
  • A random sample of internet subscribers from the west coast of the United States was asked if they were
    13·1 answer
  • Pleasee help this is due today I'll give brainliest
    14·1 answer
  • Select the three fractions that are equal to 4/12.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!