3 years ago

How many real solutions does this system of equations have? x2 +3 = y 3х — у+1 = 0

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

Answer:

Step-by-step explanation:

y = x²+3

y = 3x+1

x² + 3 = 3x +1

x² - 3x + 2 = 0

(x-2)(x-1) = 0

x = 2, 1

Two solutions

(2,7) and (1,4)

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