How many real solutions does this system of equations have? x2 +3 = y
3х — у+1 = 0
1 answer:
Answer:
Step-by-step explanation:
y = x²+3
y = 3x+1
x² + 3 = 3x +1
x² - 3x + 2 = 0
(x-2)(x-1) = 0
x = 2, 1
Two solutions
(2,7) and (1,4)
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Answer:
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Answer:
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