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3 years ago

9

Find the amount in a continuously compiunded account for the following condition. Principal, $4000; Annual interest rate, 5.1%;

time, 2 years

1 answer:

Ket [755]3 years ago

7 0

A = P*e^(rt)

Here,

A = $4000*e^(0.051*2) = $4000*e^1.02 = $4000(2.773) = $11092.78

Note: This seems very high to me.

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*THIS IS FROM K12 MIDDLE SCHOOL*

AlexFokin [52]

Answer:

7

Step-by-step explanation:

the answer is 7 because -4 in the first pair and 3 from the second ordered pair is 7.The other side is 4 because 2 and -2 are 4 places away from each other

hope it helps :)

7 0

3 years ago

Read 2 more answers

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

X^8+8x^7+15x^6−9x^5−72x^4−135x^3+8x^2+64x+120

LenaWriter [7]

Answer:

(x+3)(x+5)<em>(x-2)(x-1)</em><u>(x^2+2x+4)(x^2+x+1)</u> where the given one is bolded the 2 binomials is italicized and the 2 trinomials is underlined

Step-by-step explanation:

6 0

3 years ago

Sebastian bought a 30-pack of mechanical pencils and plans to give the same number of pencils each to 6 friends.

Korolek [52]

Answer: 5 pack

Step-by-step explanation:

From the question, we are informed that Sebastian bought a 30-pack of mechanical pencils and plans to give his friends an equal number of pencils to the 6 friends.

Therefore, each friend will get:

= 30 / 6

= 5 packs

4 0

3 years ago

Read 2 more answers

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago