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Alina [70]
3 years ago
14

TRIG EXPERTS!! PLZZZ HELP! I'LL GIVE BRAINLY TO HELPFUL ANSWER AND REPORT SCAMS!

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

28.07^{\circ}

Step-by-step explanation:

We can use basic trig. for a right triangle to solve this problem. In any right triangle, the tangent of an angle is equal to its opposite side divided by the hypotenuse (longest side) of the triangle.

The right triangle we're looking at involves the two dotted lines and an edge of the prism.

The bottom dotted line is a diagonal of the rectangular base of the prism. We can use the Pythagorean Theorem to find its length.

The Pythagorean Theorem states that for any right triangle, a^2+b^2=c^2, where a and b are the two legs of the triangle and c is the hypotenuse.

In this case, the two legs are 9 and 12 and we are solving for c:

9^2+12^2=c^2,\\81+144=c^2,\\225=c^2,\\c=15

This is theta's adjacent side. Its opposite side is an edge of the prism labelled as 8 inches. Therefore, we have the following equation:

\tan \theta = \frac{8}{15}

Take the inverse tangent of both sides:

\arctan(\tan \theta)=\arctan(\frac{8}{15})

Simplify using \arctan(\tan\theta)=\theta, \theta \in (-90^{\circ}, 90^{\circ}):

\theta=\arctan(\frac{8}{15}),\\\theta=28.07248694\approx \boxed{28.07^{\circ}}

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ki77a [65]

Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=12 represent the population standard deviation

n represent the sample size  

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

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