Answer:
None of these
Step-by-step explanation:
A <u>perpendicular bisector</u> is a segment which intersects a given segment at a 90° angle, and passes through the given segment's midpoint. Since point T divides segment SU into two parts with lengths 46 and 62 units, VT is not a perpendicular bisector.
A <u>median</u> of the triangle is a segment joining a vertex to the midpoint of the opposite side. Since point T divides segment SU into two parts with lengths 46 and 62 units, VT is not a median.
An <u>altitude</u> of the triangle is a segment passing through a vertex and perpendicular to (i.e., forming a right angle with) a line containing the base (the side opposite the vertex). The diagram doesn't show the right angle at point T (VT is not perpendicular to SU), then VT is not an altitude.
Thus, option None of These is true.
Answer:
The answer is 1. $72
Step-by-step explanation:
U can type in a calculator 6% of 1,200 or u can multiply 0.06 by 1,200 :)
First you bring the x to one side so u subtract 4x from 7x and you get the new equation as -9=3x+12 then you just solve and you get x is equal to -7
Answer:
The correct option is (b).
Step-by-step explanation:
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
You need PEMDAS
do 3·6 and then 12/6
when you subtract the product and quoetient you get 16 for the answer
