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Eduardwww [97]
2 years ago
11

The graph of a square root function has a domain of (0, ∞) and range of [1,∞). In two or more complete sentences, explain how th

e given range of the function can help you to the maximum or minimum y-value of the function.
Mathematics
1 answer:
Anit [1.1K]2 years ago
8 0

Answer:

Step-by-step explanation:

Given XZ with X(-4,3) and Z(6.-2), find the coordinates of Y if Y divides XZ one-fifth of the way from X to Z.

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A cake has a circumference of 25 1/7 inches. What is the area of the cake? Use 22/7 to approximate pi
Novosadov [1.4K]
To calculate for area given the circumference we proceed as follows:
C=2πr
where:
r=radius
thus given that C=25 1/7 in=176/7
thus plugging in our formula to solve for r we get:
176/7=2πr
thus
r=4.002~4.00 in
hence the area will be:
A=πr²
A=π×(4²)
A=50 2/7 in²


7 0
3 years ago
R + s² at r = 4, s = 1 ( Pls show work) AND NO LINKS THX UwU
icang [17]

r+s^2

4+1^2

4+2

6

Hopefully this helped

Cani get the brainliest please

5 0
2 years ago
HELP ME
Aleksandr [31]

Answer:

Sorry i don't know......!!!!!!!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the surface area of the above composite object made out of two rectangular prisms?
aleksandrvk [35]

Answer:

  550 mm^2

Step-by-step explanation:

A net can be drawn as shown in the first figure attached. Each square represents 5 mm by 5 mm, so is 25 mm^2. Altogether, there are 22 of them, so the total area is ...

  (25 mm^2)·22 = 550 mm^2

The second attachment shows that net folded up to make the given figure.

_____

In the first attachment, the green shades represent the left- and right-side faces. (Darker green is left side.) The red and blue shades represent the front- and back-side faces. The white rectangles represent the top and bottom faces. The dark black lines are the cut lines. If you want to fold the figure up, the lighter lines are the fold lines.

The second attachment is just verification that all faces are accounted for and the net actually corresponds to the given figure.

4 0
3 years ago
A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
Shalnov [3]
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand

15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3 
4.5 = x
x = 4.5
This is the length above the left hand. 

2x must be then 4.5*2 = 9 foot
This is the length below the left hand. 

Checking
4.5 + 9 + 1.5 = 15 foot 

Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
6 0
3 years ago
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