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gizmo_the_mogwai [7]
3 years ago
14

Prove(sec theta-tan theta)(sec theta+tan theta)=1​

Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Answer:

( \sec \theta -  \tan \theta)( \sec \theta +  \tan \theta)

from difference of two squares:

{ \boxed{ \tt{( {a}^{2}  -  {b}^{2}) = (a - b)(a + b) }}}

=  { \sec }^{2} \theta -  { \tan}^{2} \theta \\  = (1 + { \tan}^{2} \theta) - { \tan}^{2} \theta \\  = 1

hence proved

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Determine whether the graph below is a function.<br> Answer True if it is and False if it is not.
kramer

Answer:

<em>Answer: False</em>

Step-by-step explanation:

<em>Relations vs Functions</em>

For a given relation between two variables x and y to be a function, it must meet the following condition: every value of x must be related to one and only one value of y.

When the graph of a relation is given, we can easily tell the difference by using the vertical line test as follows:

Imagine a vertical line moving through the x-axis. If any line touches the graph of the relation at more than one point, then the relation is not a function.

If we place vertical lines through the x-axis, they would touch the function twice at some values of x.

Thus, the graph is not a function

Answer: False

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jonathans class has 30 boys,of the students of his class,60 percent are girls. how many girls are in the class
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4 years ago
Find the equation of the line which passes through the point (-4,12) and is perpendicular to the given line. Express your answer
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Answer:

y = 1/7x + 88/7

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y = mx +b

since it is perpendicular you have to get the negative reciprocal of the slope which is 1/7

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12 = 1/7(-4) + b and then solve for b

12 = -4/7 + b

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{8x-10y=20 and -7x+10y-20
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Write the equations:

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