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PolarNik [594]
2 years ago
13

The density d kg/m3 of a cube of mass m kilograms and side length x meters is given by the formula:  What is the value of d if

m = 40 and x = 0.2?​
Mathematics
1 answer:
bearhunter [10]2 years ago
6 0

Answer:

5000kg/m3

Step-by-step explanation:

Its easy to get the answer of a question from the unit.

So, it will be mass over metre cube.

Therefore, m=40kg x= (0. 2)^3 =0. 008m

40/0. 008 = 5000kg/m^3

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Find the equation of a line perpendicular to -4x+y=10 that passes through the point (-4,9)
Oliga [24]

Answer:

y=-1/4x+8

Step-by-step explanation:

To find the equation of a line that is perpendicular to a line, you would take the opposite reciprocal of the slope.

Before that, we need to change the equation into slope-intercept form.

-4x+y=10

y=4x+10

The opposite reciprocal of the slope is -1/4.

Now, let's use the point-slope formula to find our equation of the line that passes through (-4,9).

y-y1=m(x-x1)

y-9=-1/4(x-(-4))

y-9=-1/4x-1

y=-1/4x+8

4 0
2 years ago
Help please :( ASAP don’t do wrong answers
lukranit [14]

Answer:

D. 140

Step-by-step explanation:

volume equals length times width times height 7 times 4 times 5 equals 140 good luck

8 0
3 years ago
Last term of the arithmetic progression 8,15,22 is 218. Find<br>the number of terms.​
icang [17]

Answer:

31 terms.

Step-by-step explanation:

218 = 8 +  (n-1)7

210 = (n-1)7

30 + n-1

n = 31

There would be 31 terms in the given AP.

7 0
2 years ago
Theres 6 bags and 185 rasins how many are in each bag
tiny-mole [99]

Answer:

1110

Step-by-step explanation: If it was multiplication it would 1110 but you cat divide 185 by 6 so if it was 186, not 185 and you divided by 6 you would get 31 hope this helps

8 0
2 years ago
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
3 years ago
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