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SIZIF [17.4K]
2 years ago
13

Find the measure of angle 1.

Mathematics
1 answer:
Vesna [10]2 years ago
3 0

Answer:

awesome

Step-by-step explanation:

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Marla did 65 sit-ups each day for one week.Use the distributive property to find out the number of sit-ups Marla did
xxMikexx [17]
All this question is asking you to do is multiply 65 and 7. The 7 comes from the amount of days in a week. The product of these numbers is 455.

Maria did 455 sit-ups in a week.
7 0
3 years ago
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Ez question plz help
zhannawk [14.2K]

Answer:60 miles per hour

Step-by-step explanation:

5 0
3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Please help please please help
arsen [322]
46.19 should be the answer
4 0
3 years ago
A. 3 B. 23√3 C. 33–√ D. 63–√
MAXImum [283]

Answer:

I think its A.3not sure

7 0
3 years ago
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